SSE JE Electrical Engineering 24-March-2021 Shift 1 Paper

overall efficiency = 75%
Reservoir capacity (V) =3.6×106m3
Water Head (h) = 100 m
Now to calculate the potential energy, we know that
Density of water =997‌kg∕m3
g=9.8m∕s2
Put all these in formula of potential energy, we get
E = (D × V) × 9.8 × 100
E = 997 × 3.6 × 106 × 9.8 × 100
E = 3517416 × 106 J
E =(

3517416

3600

)×103‌kWh
E = 977060 kWh
Hence, total output energy can be calculated as
E' = 977060 × 0.75
∴ E' ≈ 732795 Wh ≈ 732.7 kWh