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SSC MTS Model Paper 8

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Question : 90 of 100

Marks: +1, -0

A man travelled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km per hour and partly on bicycle at 16km per hour. The distance trav- elled on the foot is

32 km
48 km
36 km
44 km

Solution:

(a) Journey on foot kmJourney on cycle (80 - x ) km

\frac{x}{8} + \frac{80 - x}{16} = 7

= \frac{2x + 80 - x}{16} = 7

= x + 80 = 16 \times 7 = 112

= x = 112 - 80 = 32 \text{ km}

Alternate :

Here x = 80 , t = 7 , u = 8 , v = 16

Time

= \frac{vt - x}{v - u}

= \frac{16 \times 7 - 80}{16 - 8}

= \left( \frac{112 - 80}{8} \right)

= \frac{32}{8} = 4

hrs

Distance travelled = 4×8 = 32kms

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