(c) Let the original speed ofaeroplane be x kmph.According to the question,x−3001200​−x1200​=2=1200(x(x−300)x−x+300​)=2=x(x−300)=21200×300​=x(x−300)=600×300=x(x−300)=600(600−300)= x = 600 kmph.Scheduled duration of flight = 1200= 2 hours600