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SSC MTS Model Paper 6

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Question : 35 of 150

Marks: +1, -0

An amount of Rs.1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and 3 the second 11% p.a. If the total interest at the end of one year is 9

\frac{3}{4}

% then the amount invested 4 in each share was:

Rs.52,500, Rs.47,500
Rs.62,500 , Rs.37,500
Rs.72,500, Rs.27,500
Rs.82,500, Rs.17,500

Solution:

Let the sum invested at 9% be Rs.x and that invested at 11% be Rs. (100000 − x) Then,

\left( \frac{x \times 9 \times 1}{100} \right) + \left[ \frac{(100000 - x) \times 11 \times 1}{100} \right]

= \left( 100000 \times \frac{39}{4} \times \frac{1}{100} \right)

= 9750

⇒ 2x = (1100000 − 975000)

= 125000

⇒ x = 62500

∴ Sum invested at 9% = Rs. 62,500

Sum invested at 11%

= Rs.(100000 − 62500)

= Rs. 37,500

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