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SSC MTS Model Paper 6

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Question : 29 of 150

Marks: +1, -0

Two vessels A and B contain milk and water mixed in the ratio 8 : 5 and 5 : 2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69

\frac{3}{13}

% milk, is:

2 : 7
3 : 5
5 : 2
5 : 7

Solution:

Let cost of 1 litre milk be Rs. 1

Milk in 1 litre mix. in A =

\frac{8}{13}

litre

C.P. of 1 litre mix. in A = Rs.

\frac{8}{13}

5 Milk in 1 litre mix. in B =

\frac{5}{7}

litre

C.P. of 1 litre mix. in B = Rs.

\frac{5}{7}

Milk in 1 litre of final mix.

= \left( \frac{900}{13} \times \frac{1}{100} \times 1 \right) = \frac{9}{13}

litre

Mean price = Rs.

\frac{9}{3}

By the rule of alligation, we have:

∴ Required ratio =

\frac{2}{91}

:

\frac{1}{13}

= 2 : 7

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