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SSC MTS Model Paper 3

Question : 28 of 150

Marks: +1, -0

Solution:

Distance travelled by Ravi = (60 − 12) km = 48 km

and distance travelled by Ajay = (60 + 12) km = 72 km

Difference between the distance travelled by them = (72 − 48) km = 24 km

Time required by Ravi =

\frac{24}{4}\ \text{ hr} = 6\ \text{ hr}

Speed of Ravi =

\frac{48}{6}\ \text{ km/hr} = 8\ \text{ km/hr}

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