(4) Let the lengths of the trains be 2x & x mTotal distance = Relative speed × time=90×185​×12=300mx+2x=300,x=100 and 2x=200and it crosses the platform in 45 seconds,∴ total distance covered in 45 seconds.=48×185​×45=600mLength of platform = 600 – 200 = 400 m