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SSC MTS Model Paper 1

Question : 41 of 150

Marks: +1, -0

Solution:

A's work = (B + C)'s work

ATQ,

(A + B)'s can complete the work in 9 hr 36 minutes i.e.

\frac{48}{5}

hrs

C can complete the work in 48 hours.

We know that

A's efficiency = (B + C)'s efficiency

C's efficiency = 1

then, A – B = 1 and A + B = 5

⇒ A's efficiency = 3 and B's efficiency = 2

Time taken by B is =

\frac{48}{2}

= 24 hr

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