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SSC MTS 5 Feb 2026 Shift 3 Paper

Question : 12 of 150

Marks: +1, -0

₹3,500

and marks it up by

35\%

. He gives two successive discounts of

20\%

and

10\%

. What is his net profit or loss percentage?

Profit of $2.8\%$
Profit of $3.8\%$
Loss of $2.8\%$
Loss of $3.8\%$

Validate

Solution:

Concept:

The net effect of a markup followed by successive discounts is found by multiplying the respective multipliers. A multiplier less than 1 indicates a loss, while greater than 1 indicates a profit.

Explanation:

First, find the net multiplier from the given percentages. Markup of 35% gives a multiplier of 1.35. A 20% discount gives a multiplier of 0.80, and a 10% discount gives 0.90. Multiply them:

1.35 \times 0.80 \times 0.90 = 0.972

. This means the final selling price is 97.2% of the cost price. Since 97.2% is less than 100%, there is a loss of

100\% - 97.2\% = 2.8\%

You can also verify with actual numbers. Cost Price (CP) = ₹3500. Marked Price (MP) = ₹3500 + 35% of ₹3500 = ₹4725. After first discount of 20%, price becomes ₹4725 × 0.80 = ₹3780. After second discount of 10%, Selling Price (SP) = ₹3780 × 0.90 = ₹3402. Loss = CP − SP = ₹3500 − ₹3402 = ₹98. Loss percentage = (98/3500) × 100 = 2.8%.

Answer:

Loss of 2.8% (Option C).

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