Concept:The last day of a year is found by counting total odd days from a reference year. Odd days are the extra days beyond complete weeks.
Explanation:First, find odd days up to the end of 1880.
1600 years have 0 odd days.
200 years have 3 odd days.
80 years (from 1601 to 1680) contain 20 leap years and 60 ordinary years.
Leap years give 2 odd days each, ordinary years give 1 odd day each.
So, odd days in 80 years = (20 × 2) + (60 × 1) = 40 + 60 = 100 days.
100 days = 14 weeks + 2 odd days.
Now, total odd days up to 1880 = 0 + 3 + 2 = 5.
1881 is an ordinary year. It has 365 days = 52 weeks + 1 odd day.
So, total odd days for the last day of 1881 = 5 + 1 = 6.
Thus, 6 odd days correspond to Saturday.
Answer:C. Saturday