Z2 – Z1 = 6m Efficiency (n) = 75% 4f = 0.006 Loss of head in the pipe line, hf=[
(4flQ2)
(3.0257d5)
] hf=[4×0.006×6×
0.052
3.0257
(2)5] hf=77.46m Head to be developed by the pump, h = 77.46 + 6 = 83.46 m HP required = (WQh/75n) HP required = 100 × 0.05 × 83.4675 × 0.75 = 74.2 HP