R 22 By comparing with R - (m - 1) (n + 1) P m – 1 = 0 ⇒ m = 1 i.e. 1 → Carbon atoms n + 1 = 2 ⇒ n = 1 i.e. 1 → Hydrogen atoms p = 2 i.e. 2 → Florine atom Now n + p + q = 2m + 2 ⇒ 1 + 2 + q = 2 × 1 + 2 ⇒ q = 1 i.e.1 → Chlorine atoms ∴CmHnFpClq⇒CHClF2