P1=1 bar, P2=8 bar, T1=295K,γ=1.4 we can find the intial volume V1 by ideal gas equation, P1V1=mRT1 1×105×V1=1×287×295 Work done using isentropic process W W=
1.4
1.4−1
×1×105×0.846[(
8
1
)
1.4−1
1.4
−1] W=240.269kW Work done using isothermal process W W=1×105×0.846×ln
8
1
W=175.920kW Therefore, the difference between the isentropic and isothermal work is, Wnet =240.269−175.920kW Wnet =64.349kW