'X' % of Moisture content is a sludge means that 'X; kg of water + (100 - x) kg of solids leads to formation of 100 Kg wet sludge. Total solids = 210 kg/day (Given) Moisture Content of sludge = 95% (Given) 95 kg of water + 5 kg of solids = 100 kg of wet sludge 5 kg of solids → 100 kg of wet sludge 1 kg of solids →
100
5
= 20 kg of wet sludge 210 kg of solids → (20 × 210) = 4200 kg/day of wet sludge Weight of wet sludge in one day = 4200 kg/day Density of wet sludge = ρws = 1.05 × 1000 = 1050 kg/m3 Volume of wet sludge, Vws=