SSC JE Civil Engineering 25-Sep-2019 Shift 1 Solved Paper

No. of bricks = (volume of brick work / volume of one brick with mortar)
Volume of one brick (without mortar)
= .19×.09×.09 = 0.001539 m ‌3
since thickness of mortar = 10 mm (0.01 m)
Volume of brick with mortar
= (0.19 + 0.01) × (0.09 + 0.1) × (0.09 + 0.1)
= 0.2 × 0.1 × 0.1 = 0.002 m ‌3
Therefore, Number of bricks =

1.0

(0.002)

= 500consider the percentage of waste as 15 %
Total no. of bricks =500+

(15×500)

100

=575
Now, Calculation for quantity of mortar
Since we need 500 no of bricks
Volume occupied by bricks = No of bricks × volume of one brick
Volume of bricks = 500 × 0.001539 = 0.7695 m‌3
Volume of mortar = Volume of BRICK WORK – Volume of BRICKS
therefore,
Volume of Mortar = 1.0 – 0.7695 = 0.2305 m‌3
The approximate proportion of dry volume of cement mortar required for brick work = 1.33 × 0.2305 = 0.3065 m‌3 (Approx 33% increment due to volume shrink after water)