Total work = LCM of individual work times Work done = Efficiency × Time Calculations: LCM of 12, 6, and 15=60 (Total work) Rajeshwar's efficiency =60∕12=5 units/day Vikram's efficiency =60∕6=10 units/day Tiger's efficiency =60∕15=4 units/day Rajeshwar worked for 2 days, so work done by him =5×2=10 units Let the total number of days the work was completed be ' x ' days. Vikram worked for ( x−3 ) days. Tiger worked for x days. Total work done = Rajeshwar's work + Vikram's work + Tiger's work 60=10+10(x−3)+4x ⇒60=10+10x−30+4x ⇒60=14x−20 ⇒80=14x ⇒x=80∕14=40∕7=5