Volume of cone (V)=(1∕3)πr2h Calculation: Let heights be h1=4k and h2=3k Let radii be r1=k and r2=2k V1=(1∕3)π(k)2(4k) ⇒V1=(1∕3)πk3×4 V2=(1∕3)π(2k)2(3k) ⇒V2=(1∕3)π4k2×3k ⇒V2=(1∕3)π4k3×3 Ratio of volumes =V1:V2 ⇒(1∕3)πk3×4:(1∕3)π4k3×3 ⇒4k3:12k3 ⇒1:3