SSC CPO Tier 1 Exam 11 Dec 2025 Shift 2

Concept:Simplify surds by breaking the number inside the square root into a perfect square factor and another factor, then combine like surds.Explanation:First, simplify $\sqrt{32}$. The largest perfect square factor of 32 is 16, so $\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}$.Next, simplify $\sqrt{18}$. The largest perfect square factor of 18 is 9, so $\sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2}$.Now substitute into the given expression: $72 + 4\sqrt{2} - 3\sqrt{2}$.Combine the terms containing $\sqrt{2}$: $4\sqrt{2} - 3\sqrt{2} = (4-3)\sqrt{2} = \sqrt{2}$.Thus the expression simplifies to $72 + \sqrt{2}$.Answer:$72 + \sqrt{2}$ (Option A)