SSC CPO SI and ASI Model Paper 1

(3) Let the original quantity ofmixture = x litre
Original quantity of water = 40% ofx = 0.4x litre
Original quantity of milk = 60% of x= 0.6x litre
New quantity of milk = (0.6x + 45)litre
Quantity of mixture after adding 45litres of milk = (x + 45) litre
Now,

0.6x+45

x+45

=0.78
⇒0.78x + 35.1 = 0.6x + 45
⇒ 0.18x = 9.9 ⇒ x = 55
∴Original quantity of mixture = 55litre