SSC CPO SI and ASI Model Paper 1

(1) According to the given condition,
The base of the isosceles triangle =Base of the parallelogram = 34 cmAnd the isosceles triangle isconstructed between the parallelsides of the parallelogram.
Therefore, the vertical distancebetween the parallel sides is thealtitude of that triangle.
Hence, the area of the triangle=

1

2

×area of parallelogram
Also, area of triangle
=

1

2

× base × altitude⇒

1

2

×34×altitude =544
⇒altitude =

544

17

altitude 32 cm