Let ideal speed of man = s km/hr and ideal time = t hours ⇒ Distance = d=st ----(i) According to ques, ⇒ d=(s+3)(t−1) ⇒ d=st−s+3t−3 Thus, using equation (i), ⇒ 3t−s=3 -----(ii) Also, d=(s−2)(t+1) ⇒ d=st+s−2t−2 ⇒ −2t+s=2 ---(iii) Adding equations (ii) and (iii), we get : ⇒ 3t−2t=3+2 ⇒ t=5 Substituting above value in equation (ii), ⇒ s=3(5)−3=15−3=12 ∴ Distence = 12×5=60km