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SSC CHSL 13 Nov 2025 Shift 3 Paper

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Question : 53 of 100

Marks: +1, -0

Simplify the expression:

sinxcotx+cosxtanx

.

$-2$
$sinxcosx$
$2cosx$
$sinx+cosx$

Solution:

Concept:

Use the identities

\cot x = \frac{\cos x}{\sin x}

and

\tan x = \frac{\sin x}{\cos x}

to rewrite the expression in terms of sine and cosine.

Explanation:

Start with

\sin x \cot x + \cos x \tan x

.

Replace

\cot x

and

\tan x

:

\sin x \cdot \frac{\cos x}{\sin x} + \cos x \cdot \frac{\sin x}{\cos x}

.

Cancel

\sin x

in the first term and

\cos x

in the second term:

\cos x + \sin x

.

Thus the expression simplifies to

\sin x + \cos x

.

Answer:

\sin x + \cos x

(Option D)

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