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SSC CGL Tier II 1 Dec 2016 Paper 1

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Question : 12 of 100

Marks: +1, -0

A water tap fills a tub in ‘p’ hours and a sink at the bottom empties it in ‘q’ hours. If p < q and both tap and sink are open, the tank is filled in ‘r’ hours; then

$\frac{1}{r}=\frac{1}{p}+\frac{1}{q}$
$\frac{1}{r}=\frac{1}{p}-\frac{1}{q}$
$r=p+q$
$r=p-q$

Solution:

(2) ∵ P < q,

∴ On opening pipe and sink together,

Part of the tub filled in 1 hour

=\frac{1}{P}-\frac{1}{q}

Clearly,

\frac{1}{r}=\frac{1}{P}-\frac{1}{q}

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