Let incomes of A and B be Rs. 3x and Rs. 2x respectively. Let the expenditures of A and B be Rs. 5y and Rs. 3y respectively. According to the question, 3x – 5y = Rs. 1000 .... (i) 2x – 3y = Rs. 1000 .... (ii) By equation (i) × 2 – (ii) × 3, 6x - 10y = 2000 6x - 9y = 300 on solving - y = - 1000 ∴ y = 1000 From equation (i), 3x – 5 × 1000 = 1000 ⇒ 3x = 1000 + 5000 = Rs. 6000 = A’s income