593 ab is divisible by 3,7 and 11 Take maximum 5 digit number by Putting ab=99 Then LCM of 3,7 and 11=231
We get 59399−32=59367 [which is divisible by 3,7 and 11] ∴ The value of a=6,b=7 So, (a2−b2+ab)=(62−72+6×7) =(36−49+42)=29 Hence, the value of a2−b2+ab is 29 .