According to the question, 5 men ×20 days =10 women ×15 days ⇒2 men =3 women ⇒
men
women
=
3
2
Now, total work =5 men ×20 days =5×3×20=300 unit First start work by =(2 men +6 women) ×5 days =(2×3+6×2)×5 =(6+12)×5 =18×5=90 unit Remaining work to complete =300−90=210 unit After than, 3 women leave the work and 1 men join So, now the work done by the (2m+3w+1m) ∴ Total days to complete the remaining work, (3m+3w)×x days =210 ⇒(3×3+3×2)×x days =210 ⇒15×x days =210 ⇒x days =14 days So, remaining work will complete in 14 days.