Given, Number 94x29 y 6 is divisible by 72 then it is also divisible by 8 and 9 (factors of 72 ) divisibility of 8 , last 3 digits of the number should be divisibile by 8 ∴ Last 3 -digits of number =9y6 for y=3,7,9y6 is divisible by 8 (∵936÷8=117 and 976÷8=122) divisibility of 9 Sum of digits of the number should be divisible by 9 . ∴ Sum of digits =9+4+x+2+9+y+6 =30+x+y for y=3, then x=3. =30+3+3=36 (which is divisible by 9 ) for y=7, then x=8 =30+8+7=45 (which is divisible by 9 ) According to the question, x≠y ∴x=8 and y=7 ∴2x+3y=2×8+3×7 =16+21=37