SSC CGL Tier-1 16-08-2015 Shift 2 Solved Paper

x = 4
⇒ equation of a line parallel to y - axis.
y = 3
⇒ Equation of a line parallel to x-axis.
Putting x = 0 in the equation
3x + 4y = 12,
3 × 0 + 4y = 12 Þ y =

12

4

= 3
∴ Co-ordinates of the point of intersection on y-axis = (0, 3) Again putting y = 0 in the equation 3x + 4y = 12,
3x + 4 × 0 = 12 ⇒ x =

12

3

= 4

AC = 3 units, BC = 4 units
∴ Area of ΔABC
=

1

2

× BC × AC
=

1

2

× 4 × 3
= 6 sq. unit