Concept:For three terms in arithmetic progression (AP), the sum of first and third equals twice the middle term.Explanation:Given terms: 7K+3, 4K−5, 2K+10.Condition for AP: 2(middle)=first+third.Thus, 2(4K−5)=(7K+3)+(2K+10).Simplify: 8K−10=9K+13.Rearrange: 8K−9K=13+10 → −K=23 → K=−23.Answer:K=−23