Concept:The ratio of the nth terms of two APs is given as n+43n+1. The ratio of their fourth terms is found by substituting n=4 if the ratio holds for all n, but we verify by solving for the AP parameters.Explanation:Let the nth terms be T1,n=a1+(n−1)d1 and T2,n=a2+(n−1)d2.Given T2,nT1,n=n+43n+1.Cross-multiply: (a1−d1+d1n)(n+4)=(a2−d2+d2n)(3n+1).Equate coefficients of n2, n, and constant