Concept:For two arithmetic progressions with the same common difference, the difference between any corresponding terms is constant.Explanation:Let the first terms be a1 and a2, and the common difference be d.The 100th terms are a1+99d and a2+99d.Their difference is (a1+99d)−(a2+99d)=a1−a2, given as 111222333.The 1,000,000th terms are a1+999999d and a2+999999d.Their difference is also a1−a2=111222333.Thus, the difference is the same for all terms.Answer:111222333