SBI PO Prelims 8 Mar 2025 Shift 2 Paper

Concept:A pair of digits $(x, y)$ qualifies if the number of digits between them in the given number equals $|x - y| - 1$ (the number of digits between them in the natural numeric series $0$ to $9$).Explanation:Given number: $5\,8\,6\,2\,9\,3\,7\,1$.Position indices: $1:5$, $2:8$, $3:6$, $4:2$, $5:9$, $6:3$, $7:7$, $8:1$.Consider unordered pairs of digits from $\{5,8,6,2,9,3,7,1\}$.For each pair, count the digits strictly between them in the number and compare to $|x - y| - 1$.Pairs that satisfy the condition:$(5,6)$ – adjacent in both number and numeric series.$(5,2)$ – two digits ($8,6$) between them; numeric gap $|5-2|-1=2$.$(5,9)$ – three digits ($8,6,2$) between them; numeric gap $|5-9|-1=3$.$(6,9)$ – two digits ($8,2$) between them; numeric gap $|6-9|-1=2$.$(9,7)$ – one digit ($3$) between them; numeric gap $|9-7|-1=1$.$(3,1)$ – one digit ($7$) between them; numeric gap $|3-1|-1=1$.No other pair satisfies the condition.Thus, total $6$ distinct pairs exist.Answer:$6$ pairs, which is more than five. Hence, Option E: More than Five.