Dividing both sides of the quadratic equation 4x2−8x−12=0 by 4 yields x2−2x−3=0 The equation x2−2x−3=0 can be factored as (x+1)(x−3)=0. This equation is true when x+1=0 or x−3=0. Solving for x gives the solutions to the original quadratic equation: x=−1 and x=3. Choices A and C are incorrect because −3 is not a solution of