Adding 4 to each side of the inequality 3p−2≥1 yields the inequality 3p+2≥5. Therefore, the least possible value of 3p+2 is 5. Choice B is incorrect because it gives the least possible value of 3p, not of 3p+2. Choice C is incorrect. If the least possible value of 3p+2 were 2, then it would follow that 3p+2≥2. Subtracting 4 from each side of this in equality would yield 3p−2≥−2. This contradicts the given inequality, 3p−2≥1.Therefore, the least possible value of 3p+2 cannot be 2. Choice D is incorrect because it gives the least possible value of p, not of 3p+2.