Let I be the initial savings.
If each successive year, 1% of the current value is added to the value of the account, then after 1 year, the amount in the account will be
I+0.01I=I(1+0.01); after 2 years, the amount in the account will be
I(1+0.01)+0.01I(1+0.01)=(1+0.01)I(1+0.01)=I(1+0.01)2;
and after t years, the amount in the account will be
I(1+0.01)t.
This is exponential growth of the money in the account.
Choice A is incorrect.
If each successive year,
2% of the initial savings, I, is added to the value of the account,
then after t years, the amount in the account will be
I+0.02It, which is linear growth.
Choice B is incorrect.
If each successive year,
1.5% of the initial savings,
I, and
100 is added to the value of the the account,
then after t years the amount in the account will be
I+(0.015I+100)t, which is linear growth.
Choice D is incorrect.
If each successive year,
100 is added to the value of the account, then after t years the amount in the account will be
I+100t, which is linear growth.