Solution:
For any value of x, say x=x0,
the point (x0,f(x0)) lies on the graph of f and the point (x0,g(x0)) lies on the graph of g.
Thus, for any values of any value of x, say x=x0,
the value of f(x0)+g(x0) is equal to the sum of the y-coordinates of the points on the graphs of f and g with x-coordinate equal to x0.
Therefore, the value of x for which f(x) + g(x) is equal to 0 will occur,
when the y-coordinates of the points representing f(x) and g(x) at the same value of x are equidistant from thex−axis and are on opposite sides of the x-axis.
Looking at the graphs, one can see that this occurs at x=−2: the point (−2,−2) lies on the graph of f, and the point (−2,2) lies on the graph of g.
Thus, at x=−2, the value of f(x)+g(x) is −2+2=0.
Choices A, C, and D are incorrect because none of these x-values satisfy the given equation, f(x)+g(x)=0.
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