SAT Mathematics Practice Test 2

Since segments LM and MN are tangent to the circle at points L and Nrespectively, angles OLM and ONM are right angles. Thus, in quadrilateral OLMN, the measure of angle O is 360°−(90°+60°+90°)=120°. Thus, in the circle, central angle O cuts off

120

360

=

1

3

of the circumference;that is,minor arc LN is

1

3

of the circumference.Since the circumference is 96,the length o f minor arc LN is

1

3

×96=32