Test Index

RRB Technician Grade 1 Model Paper 2

© examsnet.com

Question : 63 of 100

Marks: +1, -0

What is the remainder when

(x^{17} + 1)

(x + 1)

?

x
x - 1
0
1

Solution:

Concept:

For an odd value of

n

,

a^n + b^n

is divisible by

a + b

.

Hence, the remainder when

x^{17} + 1

is divided by

x + 1

is

0

.

Explanation:

The dividend is

x^{17} + 1

and the divisor is

x + 1

.

Write

1

as

1^{17}

, so the expression becomes

x^{17} + 1^{17}

.

Since

17

is odd,

x^{17} + 1^{17}

is completely divisible by

x + 1

.

So, the remainder is

0

.

Answer:

Remainder

= 0

.

Correct option: C. 0.

© examsnet.com

Go to Question:

Prev Question

Next Question