Let consecutive even numbers P, Q, R, S and T are n,n+2,n+4,n+6 and n+8
∴
n+(n−2)+(n+4)+(n+6)+(n+8)
5
=106
5n=530−20⇒n=
510
5
=102 Consecutive even numbers are 102,104,106,108 and 110 . Q×S=104×108=11232 short trick: Write two consecutive even number before 106 and two consecutive even number after 106 102,104,106,108,110 Here, P=102,Q=104,R=106,S=108 and T=110 Q×S=104×108=11232