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RRB Non Technical Model Papers 7 with solutions

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Question : 25 of 100

Marks: +1, -0

Simplify : 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 + 1÷ 2)}]

$\frac{8}{5}$
$\frac{6}{5}$
$\frac{5}{8}$
$\frac{3}{2}$

Solution:

Concept:

Use BODMAS: solve the innermost bracket first, then move outward.

Explanation:

Innermost part:

1 + 1 \div 2 = 1 + \frac{1}{2} = \frac{3}{2}

.

Next:

1 \div \frac{3}{2} = \frac{2}{3}

.

So,

\{1 + 1 \div (1 + 1 \div 2)\} = 1 + \frac{2}{3} = \frac{5}{3}

.

Then,

1 \div \frac{5}{3} = \frac{3}{5}

.

Now,

[1 + 1 \div \{1 + 1 \div (1 + 1 \div 2)\}] = 1 + \frac{3}{5} = \frac{8}{5}

.

Finally,

1 \div \frac{8}{5} = \frac{5}{8}

.

Answer:

\frac{5}{8}

, which is option C.

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