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RRB Group-D Model Paper 13 with answers for online practice

Question : 57 of 100

Marks: +1, -0

Solution:

Tips & Tricks

Triangles=

n \times \frac{n+1}{2} \times H

Where,

n= number of small triangles

H = number of ‘end to end’ horizontal lines

→ In, ∆ABC:

n= number of small triangles = 5

H = number of ‘end to end’ horizontal lines = 1 (BC)

Triangles=

5 \times \frac{5+1}{2} \times 1 = 15

Hence, Total triangles in ∆ABC = 15

Hence, there are 15 trianglesin the given figure.

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