Concept:This is a circular seating arrangement problem where positions are determined relative to each other.
Explanation:Place
G at any position.
E is third to the right of
G → count three steps clockwise from
G, so
E is at position 4 (if
G is at 1).
A is third to the right of
E → three more clockwise steps from
E, so
A is at position 7 (since
E at 4).
D is the immediate neighbour of both
B and
A. So
D must sit next to
A and next to
B. The only spot adjacent to
A (position 7) is position 6 (since 7 is adjacent to 1 and 6; 1 is
G). So
D at 6, and
B must be the other neighbour of
D, so
B at 5.
Now positions: 1:
G, 4:
E, 5:
B, 6:
D, 7:
A. Remaining positions 2 and 3 for
C and
F.
C sits to the immediate right of
F → from left of
F? In circular facing center, "immediate right" means clockwise neighbour. So if
F is at position 2, then its immediate right (clockwise) is position 3, which would be
C — that fits. So
F at 2,
C at 3.
Now counting from the left of
B: "Left of B" means anti-clockwise direction (since facing centre, left is anti‑clockwise). From
B (position 5), going anti‑clockwise we encounter:
G (pos 1),
F (pos 2),
C (pos 3),
E (pos 4). So between
F and
B, when counted from left of
B, the people sitting between them (excluding
F and
B) are
G and
E → two people.
Answer:Two people sit between
F and
B when counted from the left of
B. Hence, the correct answer is Option A (Two).
