RRB Group D 1 Dec 2025 Shift 1 Solved Paper

Concept:A number divisible by 90 must satisfy both divisibility by 10 and by 9.Explanation:Since $90 = 9 \times 10$, the number $761xy$ must be divisible by 10 and by 9.For divisibility by 10, the unit digit $y$ must be $0$. So $y = 0$.Now the number becomes $761x0$.For divisibility by 9, the sum of all digits must be a multiple of $9$.Sum $= 7 + 6 + 1 + x + 0 = 14 + x$.The smallest multiple of $9$ greater than $14$ is $18$.Thus $14 + x = 18$, giving $x = 4$.Therefore $x + y = 4 + 0 = 4$.Answer:$4$ (Option D)