RRB ALP CBT I 13 Feb 2026 Shift 1 Paper

Concept:In a concave mirror, the image position and size depend on the object's distance from the pole, focus, and centre of curvature.Explanation:When the object is placed beyond the centre of curvature $C$, the image forms between the focus $F$ and $C$.This image is real, inverted, and smaller than the object.As the object moves from beyond $C$ towards $F$, the image gradually moves away from the mirror.At $C$, the image is formed at $C$ itself, real, inverted, and equal in size to the object.When the object lies between $C$ and $F$, the image forms beyond $C$ and is real, inverted, and enlarged.When the object reaches $F$, the image is formed at infinity and is highly magnified.Thus, moving the object from beyond $C$ towards $F$ causes the image to become larger and move farther away from the mirror.The mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$, and magnification is $m = -\frac{v}{u}$.Answer:The image becomes larger and moves away from the mirror.Correct option: B.