RBI Grade B Officers 21 Nov 2015 Paper

(2) Initial quantity of milk inthe vessel = 3x litres
Initial quantity of water= x litresIn 32 litres of mixture,
Milk =

3

4

×32=24litres
Water = 8 litres
According to the question]

3x−24+32

x−8

=

4

1

⇒3x+8=4x–32
⇒4x – 3x = 32 + 8 ⇒ x = 40
∴Quantity of water = x – 8
= 40 – 8 = 32 litres
In 10 litres of mixture,
Water =

1

5

×10=2litres
∴Required quantity of water
= 32 – 2 = 30 litres