Test Index

Ratio and Proportion

Question : 39 of 112

Marks: +1, -0

Solution:

Concept:

The amount of tin in the mixture is the sum of the tin present in each alloy.

Explanation:

Alloy A weighs

60

kg and has lead and tin in the ratio

3:2

Tin fraction in alloy A is

\frac{2}{3+2} = \frac{2}{5}

Tin in alloy A =

\frac{2}{5} \times 60 = 24

kg.

Alloy B weighs

100

kg and has tin and copper in the ratio

1:4

Tin fraction in alloy B is

\frac{1}{1+4} = \frac{1}{5}

Tin in alloy B =

\frac{1}{5} \times 100 = 20

kg.

Total tin in the new alloy =

24 + 20 = 44

kg.

Answer:

44

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