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Question : 16 of 40

Marks: +1, -0

A swimming pool 9m wide and 12m long is 1m deep on the shallow side and 4m deep on the deeper side. Find its volume.

270 $m^3$
300 $m^3$
360 $m^3$
420 $m^3$

Solution: 👈: Video Solution

Concept:

The pool is a prism whose depth changes uniformly, so its cross-section is trapezoidal.

Explanation:

Average depth =

\frac{1+4}{2}=2.5\ \mathrm{m}

.

Cross-sectional area = length × average depth =

12 \times 2.5 = 30\ \mathrm{m}^2

.

Volume = cross-sectional area × width =

30 \times 9 = 270\ \mathrm{m}^3

.

Answer:

270\ \mathrm{m}^3

(Option A).

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