{array}{c|c} {Column A} & {Column B} \\ -3/4×≤ft(2/3+5/6) & 2/3×≤ft[-3/4+5/6] {array}

Correct Answer is : if the quantity in Column B is greater;

if the quantity in Column A is greater;

if the two quantities are equal;

if the relationship cannot be determined from the information given.

Correct Answer is : if the quantity in Column B is greater;

Test Index

Quantitative Comparison Practice Test 3

Question : 9 of 50

Marks: +1, -0

\begin{array}{c|c} \text{Column A} & \text{Column B} \\ -\frac{3}{4}\times\left(\frac{2}{3}+\frac{5}{6}\right) & \frac{2}{3}\times\left[-\frac{3}{4}+\frac{5}{6}\right] \end{array}

Solution:

Concept:

Simplify each column separately, then compare the two values.

Explanation:

Column A:

-\frac{3}{4}\times\left(\frac{2}{3}+\frac{5}{6}\right)

\frac{2}{3}+\frac{5}{6}=\frac{4}{6}+\frac{5}{6}=\frac{9}{6}=\frac{3}{2}

-\frac{3}{4}\times\frac{3}{2}=-\frac{9}{8}

Column B:

\frac{2}{3}\times\left[-\frac{3}{4}+\frac{5}{6}\right]

-\frac{3}{4}+\frac{5}{6}=-\frac{9}{12}+\frac{10}{12}=\frac{1}{12}

\frac{2}{3}\times\frac{1}{12}=\frac{2}{36}=\frac{1}{18}

Since

-\frac{9}{8}

is negative and

\frac{1}{18}

is positive, Column B is greater.

Answer:

Option B: if the quantity in Column B is greater.

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