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© examsnet.com
Question : 19
Total: 40
Three labourers work for 5 hours, 6 hours and 7 hours respectively in a field and get wages in the proportion of time of working in the field. Three days after they increase their working hours by 1 hour. 4 days after they increase their working hours, work in the field gets finished. If their total wages is Rs. 276, find the share of wages earned by each of them.
Rs. 78, Rs, 92, Rs. 106
Rs. 88, Rs. 87, Rs. 101
Rs. 80, Rs. 90, Rs. 106
Rs. 81, Rs. 95, Rs. 100
Validate
Solution:
Ratio of their working hours = (5 × 3 + 6 × 4) : (6 × 3 + 7 × 4) : (7 × 3 + 8 × 4) = 39 : 46 : 53
Sum of proportionals = 39 + 46 + 53 = 138
∴ Wages for the 1st labourer =
39
138
×
276
= Rs. 78
Wages for the 2nd labourer =
46
138
×
276
= Rs. 92
Wages for the 3rd labourer =
53
138
×
276
= Rs. 106
© examsnet.com
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