Geometry Practice Test 4

Perimeter of a right angled triangle = 234 m
Sum of other two sides = 234 - 97 = 137 m.
By Pythagoras theorem,
(a)2+(137−a)2 + 137 − a = 97
a2 +18,769 + a2 − 274a = 9,409
2a2 − 27a + 9,360 = 0

a2 −137a + 4,680 = 0
a2 − 72a − 65a + 4,680 = 0
(a − 72) (a − 65) = 0
a = 72,65
a = 72, b = 137 − 72 = 65